A man saved $\text{Rs. }16,500$ in $10\text{years}$. In each year after the first year, he saved $\text{Rs. }100$ more than he did in the preceding year. How much did he save in the first year?

The savings over the years follow an Arithmetic Progression (AP) where:
* Total summation ($S_n$) = $16500$
* Number of years ($n$) = $10$
* Common increase value ($d$) = $100$

The formula for the sum of an AP is:

$$S_n=\frac{n}{2}[2a+(n-1)d]$$

Substitute the known parameters into the formula:

$$16500=\frac{10}{2}[2a+(10-1)\times 100]$$

$$16500=5[2a+900]$$

$$\frac{16500}{5}=2a+900$$

$$3300=2a+900$$

$$2a=3300-900=2400$$

$$a=\frac{2400}{2}=1200$$

The man saved $\text{Rs. }1,200$ during his first year.