A man travelled a distance of 47km in 6 hours. He travelled partly on foot at a speed of 6
2
1
km/h and the rest on bicycle at a speed of 8
2
1
km/h. The distance travelled (in km) on bicycle is:
- A17
- B13
- C30
- D34
Solution & Step-by-step Explanation
Let the time spent travelling on the bicycle be t hours.
Then, the time spent travelling on foot is (6−t) hours.
Given speeds:
Speed on foot=6.5km/h
Speed on bicycle=8.5km/h
Using the relation Distance=Speed×Time:
Distance on foot+Distance on bicycle=Total Distance
6.5×(6−t)+8.5×t=47
39−6.5t+8.5t=47
39+2t=47
2t=47−39
2t=8⟹t=4 hours
The distance travelled on the bicycle is:
Distance=8.5×4=34km
Then, the time spent travelling on foot is (6−t) hours.
Given speeds:
Speed on foot=6.5km/h
Speed on bicycle=8.5km/h
Using the relation Distance=Speed×Time:
Distance on foot+Distance on bicycle=Total Distance
6.5×(6−t)+8.5×t=47
39−6.5t+8.5t=47
39+2t=47
2t=47−39
2t=8⟹t=4 hours
The distance travelled on the bicycle is:
Distance=8.5×4=34km