A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R . Assuming pulley to be - Physics MCQ FIITJEE AIEEE 2011 (Set Q) 2026 | ExamTest.live

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A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R . Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is:

Solution & Step-by-step Explanation

For the hanging mass: m g - T = ma \dots (i) For the pulley (uniform disc, I = \frac{1}{2} m R^{2}): τ = I α TR = (\frac{1}{2} m R^{2}) (\frac{a}{R}) ⟹ T = \frac{1}{2} ma \dots (ii) Substituting (ii) into (i): m g - \frac{1}{2} ma = ma m g = \frac{3}{2} ma a = \frac{2 g}{3}

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A mass m hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass m and radius R . Assuming pulley to be a perfect uniform circular disc, the acceleration of the mass m, if the string does not slip on the pulley, is:

g

\frac{2 g}{3}

\frac{g}{3}

\frac{3 g}{2}

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