A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T - Physics MCQ AIEEE 2003 2026 | ExamTest.live

mediumMCQAIEEE 20032026Physics

1 mark

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T . If the mass is increased by m, the time period becomes 5 T /3 . Then the ratio m / M is:

Solution & Step-by-step Explanation

Time period T = 2 π \frac{M}{k} . T \propto M \frac{T ^{'}}{T} = \frac{M + m}{M} \frac{5 T /3}{T} = 1 + \frac{m}{M} Squaring both sides: \frac{25}{9} = 1 + \frac{m}{M} \frac{m}{M} = \frac{25}{9} - 1 = \frac{16}{9}

Try it yourself before checking the explanation above.

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T . If the mass is increased by m, the time period becomes 5 T /3 . Then the ratio m / M is:

3/5

25/9

16/9

5/3

Practice with timed mock tests and track your performance across Physics.