A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second . If the horizontal component of ear - Physics MCQ AIEEE 2004 2026 | ExamTest.live

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A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second . If the horizontal component of earth’s magnetic field is 0.2 \times 1 0^{- 4} T, then the e.m.f. developed between the two ends of the conductor is:

Solution & Step-by-step Explanation

The induced emf for a rod rotating in a magnetic field is ε = \frac{1}{2} B ω L^{2} .Given: B = 0.2 \times 1 0^{- 4} T ω = 5 rad/s L = 1 m $ ε = \frac{1}{2} \times (0.2 \times 1 0^{- 4}) \times 5 \times 1^{2} $ ε = 0.5 \times 1 0^{- 4} = 5 \times 1 0^{- 5} V = 50 μ V Note: Using values from provided snippet 0.3 \times 1 0^{- 4} \times 5 \times 0.5 = 0.75 \times 1 0^{- 4}, but following standard question values.

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A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second . If the horizontal component of earth’s magnetic field is 0.2 \times 1 0^{- 4} T, then the e.m.f. developed between the two ends of the conductor is:

5 μ V

50 μ V

5 mV

50 mV

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