A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K . The vapour pressure of pure propyl alcohol is 200 mm . If the mole fraction of ethyl alcohol is 0.6 , its vapour pressure in pure state at the same temperature will be:

A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of 290 mm at 300 K . The vapour pressure of pure propyl alcohol is 200 mm . If the - Chemistry MCQ AIEEE 2007 2026 | ExamTest.live

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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of at . The vapour pressure of pure propyl alcohol is . If the mole fraction of ethyl alcohol is , its vapour pressure in pure state at the same temperature will be:

According to Raoult's law for a mixture of two volatile liquids: P_{t o t a l} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B} Let A be ethyl alcohol and B be propyl alcohol.Given: P_{t o t a l} = 290 mm X_{A} = 0.6 ⟹ X_{B} = 1 - 0.6 = 0.4 P_{B}^{0} = 200 mm $ 290 = (P_{A}^{0} \times 0.6) + (200 \times 0.4) $ 290 = 0.6 P_{A}^{0} + 80 0.6 P_{A}^{0} = 210 P_{A}^{0} = \frac{210}{0.6} = 350 mm

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A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of at . The vapour pressure of pure propyl alcohol is . If the mole fraction of ethyl alcohol is , its vapour pressure in pure state at the same temperature will be:

350 mm

300 mm

700 mm

360 mm

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