A network of four capacitors of capacity equal to C1 = C, C2 = 2C, C3 = 3C and C4 = 4C are connected to a battery as shown in the figure. The ratio of the charges on C2 and C4 is :

To find the ratio of the charges on $C_2$ and $C_4$, we first need to understand the equivalent capacitance of the network. However, without the specific configuration (series or parallel) of the capacitors, we can't directly calculate the equivalent capacitance or the charge distribution. Generally, in a parallel circuit, the charge on each capacitor is proportional to its capacitance, and in a series circuit, the charge on each capacitor is the same. Given the lack of specific circuit configuration in the question, let's consider a scenario where $C_2$ and $C_4$ are in a configuration that allows us to compare their charges directly, which typically would involve them being in parallel branches of the circuit. If $C_2$ and $C_4$ are in parallel, the charge on each is proportional to its capacitance. Thus, $Q_2=2Q$ and $Q_4=4Q$, where $Q$ is a constant. The ratio of the charges is then $\frac{Q_2}{Q_4}=\frac{2Q}{4Q}=\frac{1}{2}$. However, this explanation assumes a specific circuit configuration not provided in the question. The correct approach should involve analyzing the circuit's configuration to determine how charge is distributed among the capacitors. Without the exact configuration, we can't accurately determine the ratio of charges on $C_2$ and $C_4$ based on the given information.