A nucleus with mass number 240 breaks into two fragments each of mass number 120 . The binding energy per nucleon of unfragmented nuclei is 7.6 MeV wh - Physics MCQ NEET 2021 2026 | ExamTest.live

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A nucleus with mass number 240 breaks into two fragments each of mass number 120 . The binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV . The total gain in the Binding Energy in the process is:

Solution & Step-by-step Explanation

Total initial binding energy B E_{i} = 240 \times 7.6 = 1824 MeV Total final binding energy B E_{f} = (120 \times 8.5) + (120 \times 8.5) = 240 \times 8.5 = 2040 MeV Gain in Binding Energy = B E_{f} - B E_{i} Gain = 2040 - 1824 = 216 MeV

Try it yourself before checking the explanation above.

A nucleus with mass number 240 breaks into two fragments each of mass number 120 . The binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV . The total gain in the Binding Energy in the process is:

804 MeV

216 MeV

0.9 MeV

9.4 MeV

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