A number when divided by 49 leaves a remainder 9. If the same number is divided by 7, then the remainder will be:
- A1
- B3
- C2
- D0
Solution & Step-by-step Explanation
Let the number be N.
According to the problem:
N=49k+9, where k is an integer.
Now, we divide N by 7:
7
N
=
7
49k+9
=
7
49k
+
7
9
Since 49k is perfectly divisible by 7, the remainder depends only on dividing 9 by 7:
9=7×1+2
Thus, the remainder is 2.
According to the problem:
N=49k+9, where k is an integer.
Now, we divide N by 7:
7
N
=
7
49k+9
=
7
49k
+
7
9
Since 49k is perfectly divisible by 7, the remainder depends only on dividing 9 by 7:
9=7×1+2
Thus, the remainder is 2.