A, O, M, H, K and U are sitting in a circle facing the centre. A is NOT sitting next to M or U, U is to the right of H, K is to the left of M, who is opposite O. Who is to the right of O?

Let's place the 6 individuals around a circular table facing the center:M is opposite O. Let's place O at the top (12 o'clock) and M at the bottom (6 o'clock).K is to the left of M. Since they face the center, the left of M is clockwise, which means K is at the 4 o'clock position.U is to the right of H. This means H and U are adjacent, with U placed in the counter-clockwise direction relative to H.A is NOT sitting next to M or U. Since M is at 6 o'clock, A cannot be at 8 o'clock (adjacent to M). The positions left to fill are 10 o'clock, 8 o'clock, and 2 o'clock.If we place H at 8 o'clock and U at 10 o'clock (so U is to the right of H), the remaining position for A is 2 o'clock.Let's verify the condition: Is A next to M or U? At 2 o'clock, A is between O (12 o'clock) and K (4 o'clock). So A is not next to M or U. This satisfies all conditions.The final circular arrangement moving clockwise is:O (12 o'clock)A (2 o'clock)K (4 o'clock)M (6 o'clock)H (8 o'clock)U (10 o'clock)Looking at O (facing the center), the position immediately to the right of O is in the clockwise direction, which is occupied by H (at 8 o'clock).