A particle is moving eastwards with a velocity of 5 m/s . In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this tim - Physics MCQ AIEEE 2026 | ExamTest.live

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A particle is moving eastwards with a velocity of 5 m/s . In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is:

Solution & Step-by-step Explanation

Initial velocity v_{i} = 5 \hat{i} m/s .Final velocity v_{f} = 5 \hat{j} m/s .Change in velocity Δ v = v_{f} - v_{i} = 5 \hat{j} - 5 \hat{i} .Magnitude ∣Δ v ∣ = 5^{2} + (- 5)^{2} = 52 m/s .Average acceleration a_{a vg} = \frac{Δ v}{Δ t} = \frac{5 j ^ - 5 i ^}{10} = \frac{1}{2} \hat{j} - \frac{1}{2} \hat{i} .Magnitude ∣ a_{a vg} ∣ = \frac{5 2}{10} = \frac{1}{2} m/s^{2} .Direction: The vector - 5 \hat{i} + 5 \hat{j} points towards the North-West.

Try it yourself before checking the explanation above.

A particle is moving eastwards with a velocity of 5 m/s . In 10 seconds the velocity changes to 5 m/s northwards. The average acceleration in this time is:

\frac{1}{2} m/s^{2} towards north-east

\frac{1}{2} m/s^{2} towards north

zero

\frac{1}{2} m/s^{2} towards north-west

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