A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s . The work done by the force of gravity during the time the particle goes - Physics MCQ AIEEE 2006 2026 | ExamTest.live

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A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s . The work done by the force of gravity during the time the particle goes up is:

Solution & Step-by-step Explanation

Work done by gravity W = F_{g} \cdot d = - m g h .Maximum height reached h = \frac{v ^{2}}{2 g} . W = - m g (\frac{v ^{2}}{2 g}) = - \frac{1}{2} m v^{2} Mass m = 100 g = 0.1 kg, velocity v = 5 m/s . W = - \frac{1}{2} \times 0.1 \times (5)^{2} = - \frac{1}{2} \times 0.1 \times 25 W = - 1.25 J The work is negative because the force of gravity is opposite to the direction of displacement.

Try it yourself before checking the explanation above.

A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s . The work done by the force of gravity during the time the particle goes up is:

0.5 J

- 0.5 J

- 1.25 J

1.25 J

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