A particle performing uniform circular motion has angular momentum L . If its angular frequency is doubled and its kinetic energy halved, then the new - Physics MCQ AIEEE 2003 2026 | ExamTest.live

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A particle performing uniform circular motion has angular momentum L . If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is:

Solution & Step-by-step Explanation

Kinetic energy of rotation K = \frac{1}{2} I ω^{2} .Angular momentum L = I ω ⟹ I = L / ω .Substituting I : K = \frac{1}{2} (L / ω) ω^{2} = \frac{1}{2} L ω L = \frac{2 K}{ω} Given K_{2} = K /2 and ω_{2} = 2 ω : L_{2} = \frac{2 ( K /2 )}{2 ω} = \frac{K}{2 ω} = \frac{1}{4} (\frac{2 K}{ω}) = \frac{L}{4}

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A particle performing uniform circular motion has angular momentum L . If its angular frequency is doubled and its kinetic energy halved, then the new angular momentum is:

L /4

2 L

4 L

L /2

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