A particle starting from rest moves in a circle of radius r . It attains a velocity of v_0 m/s on completion of n rounds. Its angular acceleration wil - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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A particle starting from rest moves in a circle of radius r . It attains a velocity of v_{0} m/s on completion of n rounds. Its angular acceleration will be:

Solution & Step-by-step Explanation

Linear distance covered in n rounds: s = n (2 π r) .Using v^{2} = u^{2} + 2 a s : v_{0}^{2} = 0 + 2 a (2 πn r) ⟹ a = \frac{v _{0}^{2}}{4 πn r} .Angular acceleration α = \frac{a}{r} = \frac{v _{0}^{2}}{4 πn r ^{2}} .

Try it yourself before checking the explanation above.

A particle starting from rest moves in a circle of radius r . It attains a velocity of v_{0} m/s on completion of n rounds. Its angular acceleration will be:

\frac{v _{0}}{n} rad/s

\frac{v _{0}^{2}}{2 n} rad/s^{2}

\frac{v _{0}^{2}}{2 πn r ^{2}} rad/s^{2}

\frac{v _{0}^{2}}{4 πn r ^{2}} rad/s^{2}

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