A person invested a sum of Rs. 25,000 in two parts. First part at 10\% per annum simple interest and the rest

Question

A person invested a sum of Rs. 25,000 in two parts. First part at 10\% per annum simple interest and the rest at 12\% per annum simple interest. At the end of 2 years , the total interest received was Rs. 5,640 . The difference (in Rs. ) between the two parts of the sum is:

Accepted Answer

Let the first part of the investment be

X

, then the second part is

25000 - X

.Total Interest for

2 years = 5640 ⟹ Interest per year = \frac{5640}{2} = Rs. 2820

Now, write the interest equation for

1 year

:

0.10 X + 0.12 (25000 - X) = 2820

0.10 X + 3000 - 0.12 X = 2820

3000 - 2820 = 0.02 X

180 = 0.02 X ⟹ X = \frac{180}{0.02} = 9000

So, the two parts are:First part

= Rs. 9, 000

Second part

= 25000 - 9000 = Rs. 16, 000

The difference between the two parts is:

Difference = 16000 - 9000 = Rs. 7, 000

A person invested a sum of $Rs. 25, 000$ in two parts. First part at $10%$ per annum simple interest and the rest at $12%$ per annum simple interest. At the end of $2 years$ , the total interest received was $Rs. 5, 640$ . The difference (in $Rs.$ ) between the two parts of the sum is:

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A person invested a sum of Rs. 25,000 in two parts. First part at 10% per annum simple interest and the rest at 12% per annum simple interest. At the end of 2 years, the total interest received was Rs. 5,640. The difference (in Rs.) between the two parts of the sum is: