A person travelling in a straight line moves with a constant velocity v_1 for a certain distance x and with a constant velocity v_2 for the next equal - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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A person travelling in a straight line moves with a constant velocity v_{1} for a certain distance x and with a constant velocity v_{2} for the next equal distance. The average velocity v is given by the relation:

Solution & Step-by-step Explanation

Total distance d = x + x = 2 x .Time taken for first part t_{1} = \frac{x}{v _{1}} .Time taken for second part t_{2} = \frac{x}{v _{2}} .Average velocity v = \frac{Total Distance}{Total Time} = \frac{2 x}{\frac{x}{v _{1}} + \frac{x}{v _{2}}} = \frac{2}{\frac{1}{v _{1}} + \frac{1}{v _{2}}} .So, \frac{2}{v} = \frac{1}{v _{1}} + \frac{1}{v _{2}} .

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A person travelling in a straight line moves with a constant velocity v_{1} for a certain distance x and with a constant velocity v_{2} for the next equal distance. The average velocity v is given by the relation:

\frac{1}{v} = \frac{1}{v _{1}} + \frac{1}{v _{2}}

\frac{2}{v} = \frac{1}{v _{1}} + \frac{1}{v _{2}}

v = \frac{v _{1} + v _{2}}{2}

v = v_{1} v_{2}

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