A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the - Physics MCQ AIEEE 2026 | ExamTest.live

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A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km/s, the escape velocity from the surface of the planet would be:

Solution & Step-by-step Explanation

Escape velocity is v = \frac{2 GM}{R} .For the planet: M^{'} = 10 M and R^{'} = R /10 . v^{'} = \frac{2 G ( 10 M )}{R /10} = \frac{100 \cdot 2 GM}{R} = 10 \frac{2 GM}{R} = 10 v v^{'} = 10 \times 11 km/s = 110 km/s

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A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km/s, the escape velocity from the surface of the planet would be:

1.1 km/s

11 km/s

110 km/s

0.11 km/s

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