A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s . If the catching process is completed in 0.1 s , the force of the blow exerte - Physics MCQ AIEEE 2006 2026 | ExamTest.live

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A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s . If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to:

Solution & Step-by-step Explanation

Force F = \frac{Δ p}{Δ t} = \frac{m ( v - u )}{t} .Mass m = 150 g = 0.15 kg .Initial velocity u = 20 m/s, final velocity v = 0 .Time t = 0.1 s . F = \frac{0.15 \times ( 0 - 20 )}{0.1} = \frac{- 3}{0.1} = - 30 N The magnitude of the force is 30 N .

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A player caught a cricket ball of mass 150 g moving at a rate of 20 m/s . If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to:

300 N

150 N

3 N

30 N

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