A proton and an α particle are accelerated from rest to the same energy. The de-Broglie wavelength λ_p and λ_α are in the ratio: - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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A proton and an α particle are accelerated from rest to the same energy. The de-Broglie wavelength λ_{p} and λ_{α} are in the ratio:

Solution & Step-by-step Explanation

The de-Broglie wavelength is given by λ = \frac{h}{p} = \frac{h}{2 m E} .Since the energy E is the same for both: λ \propto \frac{1}{m} Ratio: \frac{λ _{p}}{λ _{α}} = \frac{m _{α}}{m _{p}} We know m_{α} = 4 m_{p} . \frac{λ _{p}}{λ _{α}} = \frac{4 m _{p}}{m _{p}} = 4 = 2 .So the ratio is 2 : 1 .

Try it yourself before checking the explanation above.

A proton and an α particle are accelerated from rest to the same energy. The de-Broglie wavelength λ_{p} and λ_{α} are in the ratio:

2 : 1

1 : 1

2 : 1

4 : 1

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