A radioactive nucleus ^A_Z X undergoes spontaneous decay in the sequence: _Z^A X 1 _Z-1 B 2 _Z-3 C 3 _Z-2 D The possible decay particles in the sequen - Physics MCQ NEET 2021 2026 | ExamTest.live

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A radioactive nucleus_{Z}^{A} X undergoes spontaneous decay in the sequence:_{Z}^{A} X 1_{Z - 1} B 2_{Z - 3} C 3_{Z - 2} D The possible decay particles in the sequence are:

Solution & Step-by-step Explanation

In radioactive decay:When the atomic number decreases by 1 (Z \to Z - 1), it is β^{+} (positron) decay.When the atomic number decreases by 2 (Z - 1 \to Z - 3), it is α decay (release of a Helium nucleus_{2}^{4} He).When the atomic number increases by 1 (Z - 3 \to Z - 2), it is β^{-} (electron) decay.The sequence is β^{+}, α, β^{-} .

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A radioactive nucleus_{Z}^{A} X undergoes spontaneous decay in the sequence:_{Z}^{A} X 1_{Z - 1} B 2_{Z - 3} C 3_{Z - 2} D The possible decay particles in the sequence are:

β^{+}, α, β^{-}

β^{-}, α, β^{+}

α, β^{-}, β^{+}

α, β^{+}, β^{-}

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