A ray of light along $x+\sqrt{3}y=\sqrt{3}$ gets reflected upon reaching $x$ -axis, the equation of the reflected rays is:

1. Find the point of incidence on the $x$ -axis (put $y=0$): $x+0=\sqrt{3}\Rightarrow P(\sqrt{3},0)$.2. Slope of incident ray: $m_i=-\frac{1}{\sqrt{3}}$.3. When a line reflects off the $x$ -axis, the slope changes sign: $m_r=\frac{1}{\sqrt{3}}$.4. Equation of reflected ray through $(\sqrt{3},0)$ with slope $\frac{1}{\sqrt{3}}$:
$$y-0=\frac{1}{\sqrt{3}}(x-\sqrt{3})$$
$$\sqrt{3}y=x-\sqrt{3}$$