A rectangular piece of paper $11\text{cm}\times 4\text{cm}$ is folded without overlapping to make a cylinder of height $4\text{cm}$, then the volume of the cylinder will be

When the paper is folded along its length to create a cylinder of height $h=4\text{cm}$, the length of the paper ($11\text{cm}$) forms the circular circumference ($2\pi r$) of the cylinder's base.
$$2\pi r=11$$
$$2\times \frac{22}{7}\times r=11⟹\frac{44}{7}r=11$$
$$r=\frac{11\times 7}{44}=\frac{7}{4}\text{cm}$$
Calculate the volume ($V$):
$$V=\pi r^{2}h=\frac{22}{7}\times \left(\frac{7}{4}\right)\times \left(\frac{7}{4}\right)\times 4$$
$$V=\frac{22\times 7}{4}=\frac{154}{4}=38.5{\text{cm}}^3$$