A school has four sections A, B, C, D of Class IX students.
| Result | Section A | Section B | Section C | Section D |
| --- | --- | --- | --- | --- |
| Students failed in both exams | 28 | 23 | 17 | 27 |
| Students failed in half-yearly but passed in annual exams | 14 | 12 | 8 | 13 |
| Students passed in half-yearly but failed in annual exams | 6 | 17 | 9 | 15 |
| Student passed in both exams | 64 | 55 | 46 | 76 |

Which section exhibits the highest pass percentage in either of the two examinations?

To find the pass percentage in "either of the two examinations", a student is considered to have passed if they passed the half-yearly exam, the annual exam, or both. The only students who did not pass either exam are those who failed in both exams.
Let's first calculate the total number of students in each section:

* ${\text{Total}}_A=28+14+6+64=112$
* ${\text{Total}}_B=23+12+17+55=107$
* ${\text{Total}}_C=17+8+9+46=80$
* ${\text{Total}}_D=27+13+15+76=131$

Now, let's find the number of students who passed in at least one of the exams (Total $-$ Failed in both):

* ${\text{Passed}}_A=112-28=84$
* ${\text{Passed}}_B=107-23=84$
* ${\text{Passed}}_C=80-17=63$
* ${\text{Passed}}_D=131-27=104$

Now, let's calculate the pass percentages for each section:

* ${\text{Percentage}}_A=\frac{84}{112}\times 100\%=75\%$
* ${\text{Percentage}}_B=\frac{84}{107}\times 100\%\approx 78.50\%$
* ${\text{Percentage}}_C=\frac{63}{80}\times 100\%=78.75\%$
* ${\text{Percentage}}_D=\frac{104}{131}\times 100\%\approx 79.39\%$

Comparing the calculated percentages, Section D has the highest pass percentage with approximately $79.39\%$.