A shell of mass is at rest initially. It explodes into three fragments having mass in the ratio . If the fragments having equal mass fly off along mutually perpendicular directions with speed , the speed of the third (lighter) fragment is:
- A
- B
- C
- D
Solution & Step-by-step Explanation
Total mass . Let masses be , , .Initially . By conservation of momentum, .Two equal masses move perpendicularly: Resultant of these two: .For total momentum to be zero, the third fragment must have momentum equal and opposite to . .
