A shopkeeper offers $3$ schemes of discounts to his customers. Which of the following schemes will fetch the minimum discount percentage?
* Scheme A: Two successive discounts of $24\%$ and $27\%$.
* Scheme B: Buy $5$ get $3$ free.
* Scheme C: Buy $6$ and get $10$.

Let's calculate the effective single discount percentage for each scheme:
**1. Scheme A: Two successive discounts of $24\%$ and $27\%$ **
Using the successive discount formula $D=x+y-\frac{xy}{100}$:

$$D_A=24+27-\frac{24\times 27}{100}$$

$$D_A=51-\frac{648}{100}=51-6.48=44.52\%$$

**2. Scheme B: Buy $5$ get $3$ free**
Here, the customer gets $3$ items free out of a total of $5+3=8$ items.

$$\text{Discount Percentage }(D_B)=\frac{\text{Free Items}}{\text{Total Items}}\times 100$$

$$D_B=\frac{3}{8}\times 100=37.5\%$$

**3. Scheme C: Buy $6$ and get $10$ **
This means the customer pays for $6$ items but walks away with $10$ items in total. Thus, $10-6=4$ items are free.

$$\text{Discount Percentage }(D_C)=\frac{\text{Free Items}}{\text{Total Items}}\times 100$$

$$D_C=\frac{4}{10}\times 100=40\%$$

Comparing the three discount values:

* Scheme A = $44.52\%$
* Scheme B = $37.5\%$
* Scheme C = $40\%$

Scheme B yields the minimum discount percentage ($37.5\%$).