A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination 30^ . The centre of mass of the cylinder has a speed - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination 3 0^{\circ} . The centre of mass of the cylinder has a speed of 4 m/s . The distance travelled by the cylinder on the inclined surface will be (g = 10 m/s^{2}):

Solution & Step-by-step Explanation

Total initial kinetic energy of rolling cylinder K = \frac{1}{2} m v^{2} (1 + \frac{k ^{2}}{R ^{2}}) .For a solid cylinder, \frac{k ^{2}}{R ^{2}} = \frac{1}{2} . K = \frac{1}{2} \times 2 \times 4^{2} \times (1 + \frac{1}{2}) = 16 \times 1.5 = 24 J .At the highest point, this energy is converted into potential energy m g h . 24 = 2 \times 10 \times h ⟹ h = 1.2 m .Distance along the incline d = \frac{h}{s i n 3 0 ^{\circ}} = \frac{1.2}{0.5} = 2.4 m .

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A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination 3 0^{\circ} . The centre of mass of the cylinder has a speed of 4 m/s . The distance travelled by the cylinder on the inclined surface will be (g = 10 m/s^{2}):

2.2 m

1.6 m

1.2 m

2.4 m

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