A sphere encloses an electric dipole with charges $\pm 3\times 10^{-6}\text{C}$. What is the total electric flux through the sphere?

According to Gauss's Law, the total electric flux $\Phi$ through a closed surface is given by $\Phi =\frac{q_{enclosed}}{{ϵ}_0}$.An electric dipole consists of two equal and opposite charges ($+q$ and $-q$).Net charge enclosed $q_{enclosed}=+3\times 10^{-6}+(-3\times 10^{-6})=0$.Therefore, $\Phi =\frac{0}{{ϵ}_0}=0$.