A square area is enclosed by fencing. If the total length of the fencing is $2440\text{m}$, find the area of the square.

The total length of the fencing around a square corresponds to its perimeter ($P$).
$$\text{Perimeter }(P)=4\times a=2440\text{m}$$

where $a$ represents the length of one side of the square.

Solve for $a$:

$$a=\frac{2440}{4}=610\text{m}$$

Now, compute the area of the square ($A$):

$$\text{Area }(A)=a^2=(610\text{m}{)}^2$$

$$A=610\times 610=3,72,100{\text{m}}^2$$