A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T . If the plane of loop is perpendicular to the direction of magnet - Physics MCQ NEET 2022 2026 | ExamTest.live

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A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T . If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is:

Solution & Step-by-step Explanation

Magnetic flux ϕ is given by ϕ = B \cdot A = B A cos θ .Here, the plane of the loop is perpendicular to the field, so the area vector is parallel to the field (θ = 0^{\circ}).Area A = (1 m)^{2} = 1 m^{2} . ϕ = (0.5 T) \times (1 m^{2}) \times cos 0^{\circ} = 0.5 \times 1 \times 1 = 0.5 Wb

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A square loop of side 1 m and resistance 1 Ω is placed in a magnetic field of 0.5 T . If the plane of loop is perpendicular to the direction of magnetic field, the magnetic flux through the loop is:

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