A started running towards north direction at 6:00 a.m. B also started running towards north direction at 10:00 a.m. At what time will they meet if the speeds of A and B are in the ratio 3:7 and they started from the same point?
- A1 p.m.
- B2 p.m.
- C1:30 p.m.
- D12:30 p.m.
Solution & Step-by-step Explanation
Let the speed of A be 3x and the speed of B be 7x.
A starts at 6:00 a.m. and B starts at 10:00 a.m. So, A runs alone for 4 hours before B starts.
Distance covered by A in 4 hours:
Distance=Speed×Time=3x×4=12x
At 10:00 a.m., B starts chasing A. Both are running in the same direction, so relative speed is:
Relative Speed=7x−3x=4x
Time taken by B to catch A:
Time=
Relative Speed
Initial Distance
=
4x
12x
=3 hours
B started at 10:00 a.m., so they meet at:
10:00 a.m.+3 hours=1:00 p.m.
A starts at 6:00 a.m. and B starts at 10:00 a.m. So, A runs alone for 4 hours before B starts.
Distance covered by A in 4 hours:
Distance=Speed×Time=3x×4=12x
At 10:00 a.m., B starts chasing A. Both are running in the same direction, so relative speed is:
Relative Speed=7x−3x=4x
Time taken by B to catch A:
Time=
Relative Speed
Initial Distance
=
4x
12x
=3 hours
B started at 10:00 a.m., so they meet at:
10:00 a.m.+3 hours=1:00 p.m.