A sum of Rs. 12,500 is distributed among A, B, C and D such that A gets Rs. 800 more than what B gets, C gets twice of what B gets and D gets Rs. 900 more than what A gets. The ratio in which D, C, B and A receive the sums is:
- A28 : 40 : 20 : 37
- B28 : 20 : 40 : 37
- C37 : 20 : 40 : 28
- D37 : 40 : 20 : 28
Solution & Step-by-step Explanation
Let the share of B be Rs. x.
According to the problem:
Share of A=x+800
Share of C=2x
Share of D=Share of A+900=(x+800)+900=x+1700
The total sum distributed is Rs. 12,500:
A+B+C+D=12500
(x+800)+x+2x+(x+1700)=12500
5x+2500=12500
5x=10000⟹x=2000
Now, we calculate individual shares:
Share of B=x=2000
Share of A=2000+800=2800
Share of C=2×2000=4000
Share of D=2000+1700=3700
The required ratio is D:C:B:A:
D:C:B:A=3700:4000:2000:2800=37:40:20:28
According to the problem:
Share of A=x+800
Share of C=2x
Share of D=Share of A+900=(x+800)+900=x+1700
The total sum distributed is Rs. 12,500:
A+B+C+D=12500
(x+800)+x+2x+(x+1700)=12500
5x+2500=12500
5x=10000⟹x=2000
Now, we calculate individual shares:
Share of B=x=2000
Share of A=2000+800=2800
Share of C=2×2000=4000
Share of D=2000+1700=3700
The required ratio is D:C:B:A:
D:C:B:A=3700:4000:2000:2800=37:40:20:28