(a) H_2O_2 + O_3 → H_2O + 2O_2 (b) H_2O_2 + Ag_2O → 2Ag + H_2O + O_2 The role of hydrogen peroxide in the above reactions is respectively: - Chemistry MCQ Chemistry | ExamTest.live | ExamTest.live

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(a) H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2} (b) H_{2} O_{2} + Ag_{2} O \to 2 Ag + H_{2} O + O_{2} The role of hydrogen peroxide in the above reactions is respectively:

A $oxidizing in (a) and reducing in (b)$
B $reducing in (a) and oxidizing in (b)$
C $reducing in (a) and (b)$
D $oxidizing in (a) and (b)$

Solution & Step-by-step Explanation

In both reactions, H_{2} O_{2} reduces the other reactant: O_{3} \to O_{2} : Ozone is reduced. H_{2} O_{2} acts as a reducing agent. Ag_{2} O \to Ag : Silver oxide (+ 1 state) is reduced to Silver metal (0 state). H_{2} O_{2} acts as a reducing agent.Thus, in both reactions, H_{2} O_{2} is a reducing agent.

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(a) H_{2} O_{2} + O_{3} \to H_{2} O + 2 O_{2} (b) H_{2} O_{2} + Ag_{2} O \to 2 Ag + H_{2} O + O_{2} The role of hydrogen peroxide in the above reactions is respectively:

A

oxidizing in (a) and reducing in (b)

B

reducing in (a) and oxidizing in (b)

C

reducing in (a) and (b)

D

oxidizing in (a) and (b)

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