A thief is spotted by a policeman from a distance of 250 m. When the policeman starts chasing, the thief also starts running. If the speed of the thie - Quantitative Aptitude MCQ Competitive Exams 2026 | ExamTest.live

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A thief is spotted by a policeman from a distance of 250 m. When the policeman starts chasing, the thief also starts running. If the speed of the thief is 16 km/h and that of the policeman is 20 km/h, how far would the thief have run before he is caught?

Solution & Step-by-step Explanation

The initial gap between the policeman and the thief = 250 m = 0.25 km . Relative speed of the policeman with respect to the thief = 20 - 16 = 4 km/h . Time taken by the policeman to catch the thief: Time = \frac{Distance}{Relative Speed} = \frac{0.25 km}{4 km/h} = \frac{1}{16} hours Distance covered by the thief during this duration: Distance = Speed of thief \times Time = 16 km/h \times \frac{1}{16} h = 1 km = 1000 m

Try it yourself before checking the explanation above.

A thief is spotted by a policeman from a distance of 250 m. When the policeman starts chasing, the thief also starts running. If the speed of the thief is 16 km/h and that of the policeman is 20 km/h, how far would the thief have run before he is caught?

850 m

950 m

1000 m

700 m

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