A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E . Due to the force qE , its - Physics MCQ NEET (UG) 2018 2026 | ExamTest.live

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A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E . Due to the force q E, its velocity increases from 0 to 6 m/s in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively:

Solution & Step-by-step Explanation

1. Acceleration a = \frac{v - u}{t} = \frac{6 - 0}{1} = 6 m/s^{2} .2. At t = 1, field is reversed, so acceleration becomes - 6 m/s^{2} .3. Displacement x_{1} (0 to 1 s) = \frac{1}{2} a t^{2} = \frac{1}{2} \times 6 \times 1^{2} = 3 m .4. t = 1 to t = 2 s: x_{2} = u t + \frac{1}{2} a t^{2} = 6 (1) + \frac{1}{2} (- 6) (1)^{2} = 3 m . (Vel becomes 0 at t = 2)5. t = 2 to t = 3 s: x_{3} = 0 (1) + \frac{1}{2} (- 6) (1)^{2} = - 3 m .Total Displacement = 3 + 3 - 3 = 3 m .Total Distance = 3 + 3 + 3 = 9 m .Average Velocity = \frac{3 m}{3 s} = 1 m/s .Average Speed = \frac{9 m}{3 s} = 3 m/s .

Try it yourself before checking the explanation above.

A toy car with charge q moves on a frictionless horizontal plane surface under the influence of a uniform electric field E . Due to the force q E, its velocity increases from 0 to 6 m/s in one second duration. At that instant the direction of the field is reversed. The car continues to move for two more seconds under the influence of this field. The average velocity and the average speed of the toy car between 0 to 3 seconds are respectively:

1 m/s, 3.5 m/s

1 m/s, 3 m/s

2 m/s, 4 m/s

1.5 m/s, 3 m/s

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