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A train starts moving from X at 5:00 p.m. and moves towards Y with a speed of 55km/hr. Another train starts moving from Y at 7:00 p.m. and moves towards X with a speed of 40km/hr. Both of them meet at 11:00 p.m. at Z. What is the ratio of distances XZ and YZ?

  1. A
    33 : 16
  2. B
    7 : 5
  3. C
    29 : 27
  4. D
    11 : 9

Solution & Step-by-step Explanation

Step 1: Calculate the distance XZ
The train from X starts at 5:00 p.m. and meets the other train at Z at 11:00 p.m.

Time traveled by the first train (t
1

)=11:00 p.m.−5:00 p.m.=6 hours
Speed of the first train (s
1

)=55km/hr
Distance XZ=s
1

×t
1

=55×6=330km
Step 2: Calculate the distance YZ
The train from Y starts at 7:00 p.m. and meets the first train at Z at 11:00 p.m.

Time traveled by the second train (t
2

)=11:00 p.m.−7:00 p.m.=4 hours
Speed of the second train (s
2

)=40km/hr
Distance YZ=s
2

×t
2

=40×4=160km
Step 3: Find the ratio of XZ and YZ

Ratio=
Distance YZ
Distance XZ

=
160
330

=
16
33


Therefore, the ratio XZ : YZ is 33:16.

Practice this question

Try it yourself before checking the explanation above.

A train starts moving from X at 5:00 p.m. and moves towards Y with a speed of 55km/hr. Another train starts moving from Y at 7:00 p.m. and moves towards X with a speed of 40km/hr. Both of them meet at 11:00 p.m. at Z. What is the ratio of distances XZ and YZ?
A
33 : 16
B
7 : 5
C
29 : 27
D
11 : 9

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