A truck is stationary and has a bob suspended by a light string in a frame attached to the truck. The truck suddenly moves to the right with an accele - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

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A truck is stationary and has a bob suspended by a light string in a frame attached to the truck. The truck suddenly moves to the right with an acceleration of a . In the frame of the truck, the pendulum will tilt:

A $to the left and the angle of inclination of the pendulum with the vertical is sin^{- 1} (\frac{a}{g})$
B $to the left and the angle of inclination of the pendulum with the vertical is cos^{- 1} (\frac{a}{g})$
C $to the left and the angle of inclination of the pendulum with the vertical is tan^{- 1} (\frac{a}{g})$
D $to the left and the angle of inclination of the pendulum with the vertical is tan^{- 1} (\frac{g}{a})$

Solution & Step-by-step Explanation

In the non-inertial frame of the truck, a pseudo force ma acts on the bob to the left.The forces are:Tension T in the string.Gravity m g downwards.Pseudo force ma to the left.At equilibrium in this frame: T sin θ = ma T cos θ = m g Dividing the equations: tan θ = \frac{ma}{m g} = \frac{a}{g} ⟹ θ = tan^{- 1} (\frac{a}{g})

Try it yourself before checking the explanation above.

A truck is stationary and has a bob suspended by a light string in a frame attached to the truck. The truck suddenly moves to the right with an acceleration of a . In the frame of the truck, the pendulum will tilt:

to the left and the angle of inclination of the pendulum with the vertical is sin^{- 1} (\frac{a}{g})

to the left and the angle of inclination of the pendulum with the vertical is cos^{- 1} (\frac{a}{g})

to the left and the angle of inclination of the pendulum with the vertical is tan^{- 1} (\frac{a}{g})

to the left and the angle of inclination of the pendulum with the vertical is tan^{- 1} (\frac{g}{a})

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