A Venn diagram shows people who bought ice-cream and drinks in a theatre. Only Ice-cream buyers = $24$, only Drink buyers = $20$. Ice-cream is sold for $\text{INR }3$ and drinks for $\text{INR }2$. If a total of $\text{INR }262$ is spent, how many people bought both a drink and an ice-cream?

Let $z$ be the number of people who bought both a drink and an ice-cream.
Given data:

* Number of people who bought only Ice-cream = $24$
* Number of people who bought only Drinks = $20$
* Price of Ice-cream = $\text{INR }3$
* Price of Drink = $\text{INR }2$

Total money spent can be formulated as:

$$\text{Cost of only ice-cream}+\text{Cost of only drinks}+\text{Cost of both items}=262$$

$$(24\times 3)+(20\times 2)+z\times (3+2)=262$$

$$72+40+5z=262$$

$$112+5z=262$$

$$5z=262-112$$

$$5z=150⟹z=\frac{150}{5}=30$$

So, $30$ people bought both.