A wire of length L , area of cross section A is hanging from a fixed support. The length of the wire changes to L_1 when mass M is suspended from its - Physics MCQ NEET 2020 E1 2026 | ExamTest.live

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A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L_{1} when mass M is suspended from its free end. The expression for Young’s modulus is:

Solution & Step-by-step Explanation

Young's Modulus Y = \frac{Stress}{Strain} = \frac{F / A}{Δ L / L} .Force F = M g .Change in length Δ L = L_{1} - L . Y = \frac{M g / A}{( L _{1} - L ) / L} = \frac{M gL}{A ( L _{1} - L )}

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A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to L_{1} when mass M is suspended from its free end. The expression for Young’s modulus is:

\frac{M g L _{1}}{A L}

\frac{M g ( L _{1} - L )}{A L}

\frac{M gL}{A L _{1}}

\frac{M gL}{A ( L _{1} - L )}

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