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mediumMCQPYQs Based Test - 05 : Maxima, Minima and Mean value theoremGeneral
1 mark (−0.33)

According to the Mean Value Theorem, for a continuous function f(x) in the interval [a, b], there exists a value ξ in this interval such that

  1. A
    f (ξ) (b - a)
  2. B
    f (b) (ξ - a)
  3. C
    f (a) (b - ξ)
  4. D
    0

Solution & Step-by-step Explanation

Mean Value Theorem for Integrals Explained

The Mean Value Theorem is a key concept in calculus that connects the average value of a function over an interval to a specific point within that interval. When applied to integrals, it helps us understand the relationship between the total area under a curve and the function's value at a particular point.

Continuous Function and Theorem Statement

For a function to satisfy the conditions of the Mean Value Theorem for Integrals, it must be continuous over a closed interval . If this condition is met, the theorem guarantees that there exists at least one value, denoted as (pronounced "xi"), within the open interval . This special value has the property that the definite integral of from to is equal to the product of the function's value at and the length of the interval .

In simpler terms, you can find a point in the interval such that the rectangle formed by the height and the width has an area exactly equal to the area under the curve of from to .

Integral Formula Derivation

The mathematical statement of the Mean Value Theorem for Integrals is given by the following formula:



Let's break down the components of this formula:

- : This represents the definite integral of the function over the interval . It calculates the net signed area between the graph of and the x-axis from to .
- : This is the value of the function at the specific point . This value is often referred to as the "average value" of the function over the interval .
- : This represents the length or width of the interval .

So, the theorem essentially states that the total area under the curve is equal to the average height of the function multiplied by the width of the interval.

Option Analysis and Correct Form

Now, let's compare the established formula from the Mean Value Theorem for Integrals with the given options to identify the correct one:
OptionExpressionAnalysis based on Theorem
1This expression directly matches the formal statement of the Mean Value Theorem for Integrals, where the integral is equal to the function value at multiplied by the length of the interval.
2This expression is incorrect because the function should be evaluated at , and the interval length should be , not .
3This expression is also incorrect. The function should be evaluated at , and the length of the interval is , not .
4This option suggests the integral is always zero, which is generally false. The integral is zero only in very specific cases (e.g., if the function itself is zero over the interval, or if positive and negative areas perfectly cancel out). It does not represent the general statement of the Mean Value Theorem.
Therefore, based on the definition and application of the Mean Value Theorem for Integrals, the integral is correctly represented by .

Practice this question

Try it yourself before checking the explanation above.

According to the Mean Value Theorem, for a continuous function f(x) in the interval [a, b], there exists a value ξ in this interval such that
A
f (ξ) (b - a)
B
f (b) (ξ - a)
C
f (a) (b - ξ)
D
0

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