Acetamide is treated with the following reagents separately. Which one of these would yield methyl amine?

This is the Hofmann Bromamide Degradation reaction. When an amide reacts with ${\text{Br}}_2$ in the presence of an alkali ($\text{NaOH}$), it is converted into a primary amine with one fewer carbon atom.
$${\text{CH}}_3{\text{CONH}}_2+{\text{Br}}_2+4\text{NaOH}\to {\text{CH}}_3{\text{NH}}_2+{\text{Na}}_2{\text{CO}}_3+2\text{NaBr}+2{\text{H}}_2\text{O}$$