Among the following ethers, which one will produce methyl alcohol on treatment with hot concentrated $\text{HI}$?

The reaction of ethers with $\text{HI}$ follows different mechanisms:In primary/secondary alkyl ethers, it follows $S_{N}2$, and ${\text{I}}^{-}$ attacks the smaller group (forming ${\text{CH}}_3\text{I}$).In tertiary alkyl ethers (Option C), it follows $S_{N}1$ because a stable tertiary carbocation $(C{H}_3{)}_3{C}^{+}$ can form.
$$\text{tert-butyl-methyl ether}+\text{HI}\to (C{H}_3{)}_{3}C-I+{\text{CH}}_3\text{OH}$$
Thus, methyl alcohol is produced in the case of the tertiary alkyl group.