An automobile travelling with speed of 60 km/h , can brake to stop within a distance of 20 m . If the car is going twice as fast, i.e 120 km/h , the s - Physics MCQ AIEEE 2004 2026 | ExamTest.live

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An automobile travelling with speed of 60 km/h, can brake to stop within a distance of 20 m . If the car is going twice as fast, i.e 120 km/h, the stopping distance will be:

Solution & Step-by-step Explanation

Stopping distance s is given by the equation v^{2} = u^{2} + 2 a s .Since it stops, v = 0 . 0 = u^{2} - 2 a s ⟹ s = \frac{u ^{2}}{2 a} Assuming constant retardation a : s \propto u^{2} If the initial speed u is doubled, the stopping distance becomes 2^{2} = 4 times.New distance = 4 \times 20 m = 80 m .

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An automobile travelling with speed of 60 km/h, can brake to stop within a distance of 20 m . If the car is going twice as fast, i.e 120 km/h, the stopping distance will be:

20 m

40 m

60 m

80 m

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