An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 × 10^-2 nm , the - Physics MCQ NEET 2020 E1 2026 | ExamTest.live

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An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 \times 1 0^{- 2} nm, the potential difference is:

Solution & Step-by-step Explanation

For an electron: λ \approx \frac{1.227}{V} nm .Given λ = 1.227 \times 1 0^{- 2} nm . 1.227 \times 1 0^{- 2} = \frac{1.227}{V} V = \frac{1}{1 0 ^{- 2}} = 100 \Rightarrow V = 10 0^{2} = 10, 000 V = 1 0^{4} V

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An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is 1.227 \times 1 0^{- 2} nm, the potential difference is:

10 V

1 0^{2} V

1 0^{3} V

1 0^{4} V

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