An ideal coil of 10 H is connected in series with a resistance of 5 Ω and a battery of 5 V . 2 seconds after the connection is made, the current flowi - Physics MCQ AIEEE 2007 2026 | ExamTest.live

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An ideal coil of 10 H is connected in series with a resistance of 5 Ω and a battery of 5 V . 2 seconds after the connection is made, the current flowing in amperes in the circuit is:

Solution & Step-by-step Explanation

In a series RL circuit, the growth of current i is given by: i = i_{0} (1 - e^{- Rt / L}) where i_{0} = \frac{V}{R} = \frac{5}{5} = 1 A .The time constant τ = \frac{L}{R} = \frac{10}{5} = 2 s .At t = 2 s : i = 1 \times (1 - e^{- 5 \times 2/10}) = 1 \times (1 - e^{- 1}) i = 1 - e^{- 1}

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An ideal coil of 10 H is connected in series with a resistance of 5 Ω and a battery of 5 V . 2 seconds after the connection is made, the current flowing in amperes in the circuit is:

(1 - e)

e

e - 1

1 - e^{- 1}

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