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An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass . The piston and cylinder have equal cross sectional area . When the piston is in equilibrium, the volume of the gas is and its pressure is . The piston is slightly displaced from the equilibrium position and released. Assuming that the system is completely isolated from its surrounding, the piston executes a simple harmonic motion with frequency:

  1. A
    \frac{1}{2\pi} \sqrt{\frac{V_0 MP_0}{A^2\gamma}}
  2. B
    \frac{1}{2\pi} \sqrt{\frac{A^2 \gamma P_0}{MV_0}}
  3. C
    \frac{1}{2\pi} \sqrt{\frac{MV_0}{A^2 \gamma P_0}}
  4. D
    \frac{1}{2\pi} \sqrt{\frac{A\gamma P_0}{V_0 M}}

Solution & Step-by-step Explanation

Since the system is isolated, the process is adiabatic.For an adiabatic process, .If piston is displaced by , ..Restoring force .Acceleration .This is SHM with .Frequency .

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An ideal gas enclosed in a vertical cylindrical container supports a freely moving piston of mass . The piston and cylinder have equal cross sectional area . When the piston is in equilibrium, the volume of the gas is and its pressure is . The piston is slightly displaced from the equilibrium position and released. Assuming that the system is completely isolated from its surrounding, the piston executes a simple harmonic motion with frequency:
A
\frac{1}{2\pi} \sqrt{\frac{V_0 MP_0}{A^2\gamma}}
B
\frac{1}{2\pi} \sqrt{\frac{A^2 \gamma P_0}{MV_0}}
C
\frac{1}{2\pi} \sqrt{\frac{MV_0}{A^2 \gamma P_0}}
D
\frac{1}{2\pi} \sqrt{\frac{A\gamma P_0}{V_0 M}}

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