An object is initially facing East. It undergoes the given below sequence of turns:
1. Turns $145^{\circ }$ counter clockwise
2. Then turns $190^{\circ }$ clockwise
3. Finally, turns $135^{\circ }$ counter clockwise
In which direction is the object facing finally?

Let's designate counter-clockwise (CCW) turns as positive values (+) and clockwise (CW) turns as negative values (-).
Net angular turn calculation:

$$\text{Net Turn}=(+145^{\circ })+(-190^{\circ })+(+135^{\circ })$$

$$\text{Net Turn}=145^{\circ }-190^{\circ }+135^{\circ }=90^{\circ }\text{ (positive, so CCW)}$$

Initially, the object is facing East.
Rotating $90^{\circ }$ counter-clockwise (left turn) from East leads to the North direction.

Therefore, the object is facing North finally.