An organic compound (${\text{C}}_3{\text{H}}_9\text{N}$) ($A$), when treated with nitrous acid, gave an alcohol and ${\text{N}}_2$ gas was evolved. ($A$) on warming with ${\text{CHCl}}_3$ and caustic potash gave ($C$) which on reduction gave isopropylmethylamine. Predict the structure ($A$).

1. Compound $A$ (${\text{C}}_3{\text{H}}_9\text{N}$) reacts with ${\text{HNO}}_2$ to give alcohol and ${\text{N}}_2⟹A$ is a primary ($1^{\circ }$) amine.2. $A$ reacts with ${\text{CHCl}}_3+\text{KOH}$ (Carbylamine reaction) to give $C$ (an isocyanide, $\text{R}-\text{NC}$).3. Reduction of isocyanide ($\text{R}-\text{NC}$) gives a secondary amine ($\text{R}-{\text{NHCH}}_3$).4. The product is isopropylmethylamine (${\text{CH}}_3{\text{CH(CH}}_3{\text{)NHCH}}_3$). This means the original $R$ group was an isopropyl group.Therefore, $A$ is isopropylamine: ${\text{CH}}_3\text{CH}({\text{NH}}_2){\text{CH}}_3$.