Anita and Anand can complete a work in 12 days and 18 days respectively. They undertook to complete that work for ₹48,000. With the help of Arun, they completed the work in 6 days. Find the sum of the shares of Anita and Anand (in ₹).
- A40000
- B8000
- C16000
- D24000
Solution & Step-by-step Explanation
Let the total work be the LCM of individual days (12,18,6) = 36 units.
Now, let's find their individual efficiencies (work done per day):
Efficiency of Anita (E
Anita
) =
12
36
=3 units/day
Efficiency of Anand (E
Anand
) =
18
36
=2 units/day
When Anita, Anand, and Arun work together, they complete the work in 6 days.
Combined Efficiency (E
Anita
+E
Anand
+E
Arun
) =
6
36
=6 units/day
Now, find the efficiency of Arun:
3+2+E
Arun
=6⟹E
Arun
=1 unit/day
Wages are distributed in proportion to the total work done or efficiency since they work together for the same amount of time:
Ratio of shares=E
Anita
:E
Anand
:E
Arun
=3:2:1
Total ratio parts = 3+2+1=6 parts
Total amount = ₹48,000
We need to find the sum of the shares of Anita and Anand:
Combined share fraction=
6
3+2
=
6
5
Combined share value=
6
5
×48000=5×8000=₹40,000
Now, let's find their individual efficiencies (work done per day):
Efficiency of Anita (E
Anita
) =
12
36
=3 units/day
Efficiency of Anand (E
Anand
) =
18
36
=2 units/day
When Anita, Anand, and Arun work together, they complete the work in 6 days.
Combined Efficiency (E
Anita
+E
Anand
+E
Arun
) =
6
36
=6 units/day
Now, find the efficiency of Arun:
3+2+E
Arun
=6⟹E
Arun
=1 unit/day
Wages are distributed in proportion to the total work done or efficiency since they work together for the same amount of time:
Ratio of shares=E
Anita
:E
Anand
:E
Arun
=3:2:1
Total ratio parts = 3+2+1=6 parts
Total amount = ₹48,000
We need to find the sum of the shares of Anita and Anand:
Combined share fraction=
6
3+2
=
6
5
Combined share value=
6
5
×48000=5×8000=₹40,000