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Anita and Anand can complete a work in 12 days and 18 days respectively. They undertook to complete that work for ₹48,000. With the help of Arun, they completed the work in 6 days. Find the sum of the shares of Anita and Anand (in ₹).

  1. A
    40000
  2. B
    8000
  3. C
    16000
  4. D
    24000

Solution & Step-by-step Explanation

Let the total work be the LCM of individual days (12,18,6) = 36 units.
Now, let's find their individual efficiencies (work done per day):

Efficiency of Anita (E
Anita

) =
12
36

=3 units/day

Efficiency of Anand (E
Anand

) =
18
36

=2 units/day

When Anita, Anand, and Arun work together, they complete the work in 6 days.

Combined Efficiency (E
Anita

+E
Anand

+E
Arun

) =
6
36

=6 units/day

Now, find the efficiency of Arun:

3+2+E
Arun

=6⟹E
Arun

=1 unit/day
Wages are distributed in proportion to the total work done or efficiency since they work together for the same amount of time:

Ratio of shares=E
Anita

:E
Anand

:E
Arun

=3:2:1
Total ratio parts = 3+2+1=6 parts
Total amount = ₹48,000

We need to find the sum of the shares of Anita and Anand:

Combined share fraction=
6
3+2

=
6
5


Combined share value=
6
5

×48000=5×8000=₹40,000

Practice this question

Try it yourself before checking the explanation above.

Anita and Anand can complete a work in 12 days and 18 days respectively. They undertook to complete that work for ₹48,000. With the help of Arun, they completed the work in 6 days. Find the sum of the shares of Anita and Anand (in ₹).
A
40000
B
8000
C
16000
D
24000

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