Arjun is facing east. He walks 10m in this direction, then turns left and walks for another 10m, then he turns right to walk 25m and from there he walks another 10m towards south. Finally, he walks 50m to his left. How far is he from his original position?
- A85 m
- B80 m
- C75 m
- D90 m
Solution & Step-by-step Explanation
Let's trace Arjun's path step by step using coordinates starting at (0,0):
Starts at (0,0) facing East.
Walks 10m East → reaches (10,0).
Turns left (North) and walks 10m → reaches (10,10).
Turns right (East) and walks 25m → reaches (10+25,10)=(35,10).
Walks 10m South → reaches (35,10−10)=(35,0).
Currently facing South, he takes a left turn (which means moving towards the East direction) and walks 50m → reaches (35+50,0)=(85,0).
Total horizontal distance from the origin (0,0) to the final position (85,0) is:
Distance=85−0=85m
Arjun is 85m away from his initial starting position.
Starts at (0,0) facing East.
Walks 10m East → reaches (10,0).
Turns left (North) and walks 10m → reaches (10,10).
Turns right (East) and walks 25m → reaches (10+25,10)=(35,10).
Walks 10m South → reaches (35,10−10)=(35,0).
Currently facing South, he takes a left turn (which means moving towards the East direction) and walks 50m → reaches (35+50,0)=(85,0).
Total horizontal distance from the origin (0,0) to the final position (85,0) is:
Distance=85−0=85m
Arjun is 85m away from his initial starting position.