Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of ma - PHYSICS MCQ NEET 2019 2026 | ExamTest.live

easyMCQNEET 20192026PHYSICS

1 mark

Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass m when taken to a height h from the surface of the earth (of radius R and mass M), is given by:

Solution & Step-by-step Explanation

Initial P.E. at surface U_{i} = - \frac{GM m}{R} .Final P.E. at height h from surface U_{f} = - \frac{GM m}{R + h} .Change in P.E. Δ U = U_{f} - U_{i} = - \frac{GM m}{R + h} - (- \frac{GM m}{R}) Δ U = GM m (\frac{1}{R} - \frac{1}{R + h}) = GM m \frac{R + h - R}{R ( R + h )} = \frac{GM mh}{R ( R + h )} .

Try it yourself before checking the explanation above.

Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass m when taken to a height h from the surface of the earth (of radius R and mass M), is given by:

- \frac{GM m}{R + h}

\frac{GM mh}{R ( R + h )}

m g h

\frac{GM m}{R + h}

Practice with timed mock tests and track your performance across PHYSICS.